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Proton in magnetic field
A proton with a velocity of 1.5*10^6 is put in a magnetic field of 150 T that is at a 30 degree angle with the protons initial velocity. After 4 seconds, what is the speed of the proton?
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Recall that the force on a charged particle in a magnetic field it F=qvxB. This is always perpendicular to the velocity. Remember from circular motion that forces perpendicular to the velocity never causes changes in speed, only direction.