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Torque on a fishing pole
A fisherman grips his 3.0 m long pole at a point 45 cm up from the bottom end pulling to keep his pole steady while a fish tugs on the line at the other end with a force of 15 N. The pole makes an angle of 60 degrees with the horizontal and the line at the top end of hte pole comes off at a right angle from the pole. The pole has a mass of 2.5 kg. What force must the fisherman apply and in what direction to keep the pole steady?
Customer support service by UserEcho
Make sure you consider the different components of the force separately. In other words, find the force in the x direction and the y direction independently because there is no reason for them to be coupled anyway. Look at the forces from the fish and from the fishing pole (mass) I believe. Add these components up
F^2 = F_x^2 + F_y^2
and then you have the total force.
However, to find the direction consider the flat ground (facing the water) to be ø = 0 degrees and use trig (most likely tan(ø)) to find the angle of the direction. Hopefully you'll realize that the angle is greater than 90 degrees.